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AaBbCc自交基因型怎么算

更新时间: 2020-10-31 00:00:00     

后代中与亲本基因型相同的概率为1/8,因为出现Aa、Bb、Cc的概率各为1/2,将它们相乘即可。(算法跟出现纯合子的概率一样)

与亲本表现型相同就是求显性基因即都含有大写字母(A、B、C),则有AABbCc、AaBbCc、AaBBCc、AaBbCC这四种,AA、BB、CC的概率都是1/4,所以AABbCc=1/4*1/2*1/2=1/16,同理,AaBBCc、AaBbCC的概率也是1/16,AaBbCc的概率是1/2*1/2*1/2=1/8,相加起来就行了,1/16+1/16+1/16+1/8=5/16。

也可求隐性基因的概率来求得,求出隐性基因概率后,用1减去就可得到了。

关键词: aabbcc 基因 怎么

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